Odpowiedź:
[tex]a)\ \ 8\cdot3^6+9^3=8\cdot3^6+(3^2)^3=8\cdot3^6+3^6=8\cdot3^6+1\cdot3^6=(8+1)\cdot3^6=9\cdot3^6=\\\\3^2\cdot3^6=3^{2+6}=3^8\\\\\\b)\ \ 6\cdot5^6-25^3=6\cdot5^6-(5^2)^3=6\cdot5^6-5^6=6\cdot5^6-1\cdot5^6=(6-1)\cdot5^6=5\cdot5^6=\\\\=5^{1+6}=5^7[/tex]
[tex]c)\ \ 5\cdot2^9+6\cdot8^3-3\cdot512=5\cdot2^9+6\cdot(2^3)^3-3\cdot2^9=5\cdot2^9+6\cdot2^9-3\cdot2^9=\\\\=(5+6-3)\cdot2^9=8\cdot2^9=2^3\cdot2^9=2^{3+9}=2^{12}[/tex]
