Cześć ;-)
a)
[tex](\frac{2}{3})^2\cdot3-\frac{1}{2}\cdot0,2=\frac{2^2}{3^2}\cdot3-\frac{1}{2}\cdot\frac{2}{10}=\\\\=\frac{4}{9}\cdot3-\frac{1}{2}\cdot\frac{1}{5}=\frac{4}{3}-\frac{1}{10}=\frac{40}{30}-\frac{3}{30}=\frac{37}{30}=1\frac{7}{30}[/tex]
b)
[tex]\frac{1}{6}\cdot4+\frac{2}{3}:1\frac{1}{2}=\frac{4}{6}+\frac{2}{3}:\frac{3}{2}=\\\\=\frac{2}{3}+\frac{2}{3}\cdot\frac{2}{3}=\frac{2}{3}+\frac{4}{9}=\frac{6}{9}+\frac{4}{9}=\frac{10}{9}=1\frac{1}{9}[/tex]
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