Odpowiedź:
[tex]a)\ \ 2\frac{5}{7}+1\frac{5}{6}=2\frac{30}{42}+1\frac{35}{42}=3\frac{65}{42}=4\frac{23}{42}\\\\\\b)\ \ (3\frac{1}{3})^2=(\frac{10}{3})^2=\frac{100}{9}=11\frac{1}{9} \\\\\\c)\ \ 5\frac{7}{8}-3\frac{2}{3}=5\frac{21}{24}-3\frac{16}{24}=2\frac{5}{24}\\\\\\d)\ \ 5\frac{4}{9}-3\frac{5}{8}=5\frac{32}{72}-3\frac{45}{72}=4\frac{104}{72}-3\frac{45}{72}=1\frac{59}{72}[/tex]
[tex]e)\ \ \frac{11}{\not12_{3}}\cdot\frac{\not4^1}{5}=\frac{11}{15}\\\\\\f)\ \ \frac{2}{3}:\frac{8}{27}=\frac{\not2^1}{\not3_{1}}\cdot\frac{\not27^9}{\not8_{4}}=\frac{9}{4}=2\frac{1}{4}\\\\\\g)\ \ 1\frac{3}{5}\cdot2\frac{1}{4}=\frac{\not8^2}{5}\cdot\frac{9}{\not4_{1}}=\frac{18}{5}=3\frac{3}{5}\\\\\\h)\ \ \frac{7}{11}:1\frac{5}{9}=\frac{7}{11}:\frac{14}{9}=\frac{\not7^1}{11}\cdot\frac{9}{\not14_{2}}=\frac{9}{22}[/tex]
