Odpowiedź :
Cześć ;-)
[tex]5\dfrac{2}{3}+1\dfrac{3}{5}=5\dfrac{\boxed{10}}{15}+1\dfrac{\boxed9}{15}=6\dfrac{19}{15}=\boxed7\dfrac{\boxed{4}}{15}[/tex]
Pozdrawiam!
Cześć ;-)
[tex]5\dfrac{2}{3}+1\dfrac{3}{5}=5\dfrac{\boxed{10}}{15}+1\dfrac{\boxed9}{15}=6\dfrac{19}{15}=\boxed7\dfrac{\boxed{4}}{15}[/tex]
Pozdrawiam!