Bardzo proszę o pomoc
a)7½+4 7/10=
b)5⅙-4⅝=
c)9⅛-4 7/12=
d)6 1/7-4⅚=
e)4⅙×3 7/15​


Odpowiedź :

Cześć ;-)

Obliczenia

[tex]a] \ 7\frac{1}{2}+4\frac{7}{10}=7\frac{5}{10}+4\frac{7}{10}=11\frac{12}{10}=11\frac{6}{5}=12\frac{1}{5}\\\\b] \ 5\frac{1}{6}-4\frac{5}{8}=5\frac{4}{24}-4\frac{15}{24}=4\frac{28}{24}-4\frac{15}{24}=\frac{13}{24}\\\\c] \ 9\frac{1}{8}-4\frac{7}{12}=9\frac{3}{24}-4\frac{14}{24}=8\frac{27}{24}-4\frac{14}{24}=4\frac{13}{24}\\\\d] \ 6\frac{1}{7}-4\frac{5}{6}=6\frac{6}{42}-4\frac{35}{42}=5\frac{48}{42}-4\frac{35}{42}=1\frac{13}{42}[/tex]

[tex]e] \ 4\frac{1}{6}\cdot3\frac{7}{15}=\frac{\not25^5}{\not6_3}\cdot\frac{\not52^{26}}{\not15_3}=\frac{130}{9}=14\frac{4}{9}[/tex]

Pozdrawiam!

a)7½+4 7/10=7 5/10 +4 7/10=11 12/10=12 2/10=12 1/5

b)5⅙-4⅝=5  4/24 -4 15/25=4 28/24-4 15/24=13/24

c)9⅛-4 7/12=9 3/24 -4 14/24=8 27/24- 4 14/24=4 13/24

d)6 1/7-4⅚= 6 6/42 -4 35/42=5 48/42 - 4 35/42=1 13/42

e)4⅙×3 7/15= 25/6* 52/15=130/9=14 4/9