[tex]\sqrt{121} = \sqrt{11^{2}} = 11\\\\\\\sqrt{0,09} = \sqrt{0,3^{2}} = 0,3\\\\\\\sqrt{\frac{49}{81}} = \sqrt{(\frac{7}{9})^{2}}} = \frac{7}{9}\\\\\\\sqrt{1\frac{11}{25}} = \sqrt{\frac{1\cdot25+11}{25}} = \sqrt{\frac{36}{25}} = \sqrt{(\frac{6}{5})^{2}} = \frac{6}{5} = 1\frac{1}{5}[/tex]
