[tex]\frac{1}{2}+ \frac{1}{5}+ \frac{1}{10}= \frac{5}{10}+ \frac{2}{10}+ \frac{1}{10}= \frac{8}{10}=\frac{4}{5}\\\\\\ \frac{3}{8}-\frac{3}{10}+ \frac{3}{40}=\frac{15}{40}-\frac{12}{40}+ \frac{3}{40}=\frac{3}{40}+\frac{3}{40}=\frac{6}{40}=\frac{3}{20}\\\\\\ \frac{1}{6}+ \frac{1}{10}+ \frac{1}{15}=\frac{5}{30}+ \frac{3}{30}+ \frac{2}{30}=\frac{10}{30}=\frac{1}{3}\\\\\\ \frac{3}{4}+ \frac{2}{5}- \frac{1}{10}=\frac{15}{20}+ \frac{8}{20}- \frac{2}{20}=\frac{23}{20}-\frac{2}{20}=\frac{21}{20}=1\frac{1}{20}\\\\\\ \frac{7}{8}-( \frac{5}{12}+ \frac{3}{16}) =\frac{42}{48}-( \frac{20}{48}+ \frac{9}{48})=\frac{42}{48} -\frac{29} {48}=\frac{13}{48}[/tex]
[tex]\\\\\\Aby\ wykonac\ dzialanie\ nalezy, sprowadzic\ ulamki\\\\ do\ wspolnego\ mianownika.[/tex]
