[tex](2,7\times\frac{1}{9}+6,4\times\frac{1}{4})-(3,6:1\frac{1}{2}-2\frac{1}{4}:1,5) = (\frac{2,7}{9}+\frac{6,4}{4})-(\frac{3,6}{1,5}-\frac{2,25}{1,5})=\\\\=(\frac{27}{90}+\frac{64}{40})-(\frac{360}{150}-\frac{225}{150}) = (\frac{3}{10}+\frac{16}{10})-\frac{135}{150} = \frac{19}{10}-\frac{9}{10} = \frac{10}{10} = 1[/tex]
