Odpowiedź:
1) [tex]9^{4}[/tex], 2)4, 3)[tex]a^{3}[/tex]
Szczegółowe wyjaśnienie:
1) [tex]26*9^{2} +5*9^{3} +90*9=26*9^{2} +5*9^{2}*9 +9*10*9 = 26*9^{2} +5*9*9^{2} +10*9^{2}=(26+5*9+10)*9^{2}=(26+45+10)*9^{2}=(81)*9^{2}=9^{2}*9^{2} = 9^{4}[/tex]
2) [tex]\frac{4^{25}:(4^2*4)^4}{4^{10}*9+7*4^{10}} = \frac{4^{25}:(4^{2+1})^4}{4^{10}*(9+7)}} = \frac{4^{25}:(4^{3})^4}{4^{10}*(16)}} = \frac{4^{25}:4^{3*4}}{4^{10}*(4^2)}} = \frac{4^{25}:4^{12}}{4^{10+2}}} = \frac{4^{25-12}}{4^{12}}} = \frac{4^{13}}{4^{12}}} = 4^{13-12} = 4^1=4[/tex]
3) [tex]\frac{(a^{2})^7:a^{4}}{a^{6}*a} = \frac{(a^{2*7}):a^{4}}{a^{6+1}}= \frac{a^{14}:a^{4}}{a^{7}} = \frac{a^{14-4}}{a^{7}} = \frac{a^{10}}{a^{7}} = a^{10-7}=a^3[/tex]
