[tex]8(1+\frac{x+2}{4}) -3=0\\\\8\cdot1 + 8\cdot\frac{x+2}{4} -3=0\\\\8+2(x+2)-3 = 0\\\\8 + 2x + 4 - 3 = 0\\\\2x+9 = 0\\\\2x = -9 \ \ /:2\\\\x = -4,5[/tex]
