c]
[tex]4x^2+4x+1=0\\\\(2x+1)^2=0\\\\2x+1=0\\\\2x=-1 \ \ |:2\\\\x=-\frac{1}{2}[/tex]
e]
[tex]\frac{1}{4}x^2+\frac{1}{2}=x-\frac{1}{2}\\\\\frac{1}{4}x^2-x+\frac{1}{2}+\frac{1}{2}=0\\\\\frac{1}{4}x^2-x+1=0 \ \ |\cdot4\\\\x^2-4x+4=0\\\\(x-2)^2=0\\\\x-2=0\\\\x=2[/tex]
