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Rozwiązane

1. Oblicz
a) (3⁻²)²
b) (1/2)⁻⁴
c) 2⁻³ * (1/2)⁻³
d) 9³ * 3⁻⁵

Odpowiedź :

[tex]a] \ (3^{-2})^2=3^{-2\cdot2}=3^{-4}=(\frac{1}{3})^4=\frac{1}{81}\\\\b] \ (\frac{1}{2})^{-4}=2^4=16\\\\c] \ 2^{-3}\cdot(\frac{1}{2})^{-3}=(2\cdot\frac{1}{2})^{-3}=1^{-3}=1\\\\d] \ 9^3\cdot3^{-5}=(3^2)^3\cdot3^{-5}=3^6\cdot3^{-5}=3^{6+(-5)}=3^1=3[/tex]

ZbiorJviz

Odpowiedź:

(3⁻²)² = 3⁻²ˣ² = 3⁻⁴ = 1/3⁴ = 1/81

(1/2)⁻⁴ = (2/1)⁴ = 2⁴ = 16

2⁻³ × (1/2)⁻³ = ( 2× 1/2 )⁻³ = 1⁻³ = 1³ = 1

9³ × 3⁻⁵ = (3²)³ × 3⁻⁵ = 3⁶ × 3⁻⁵ = 3⁶⁺⁽⁻⁵⁾ = 3¹ = 3

Szczegółowe wyjaśnienie:

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