Witam.
[tex]Pole \: trapezu: \: \frac{(a + b ) \times h}{2} [/tex]
Dane: Szukane:
a=4cm h=?
b=8cm
P=24cm²
[tex] \frac{(4cm \times 8cm) \times h}{2} = 24cm ^{2} \: \: \: \: | \times 2[/tex]
[tex](4cm + 8cm) \times h = 48c {m}^{2} [/tex]
[tex]12cm\times h = 4 {8}cm^{2} \: \: \: | \div 12cm[/tex]
[tex]h = 4cm[/tex]
Sprawdzenie:
[tex] \frac{(4cm + 8cm) \times 4cm}{2} = 24c {m}^{2} [/tex]
[tex] \frac{12cm \times 4cm}{2} = 24c {m}^{2} [/tex]
[tex] \frac{48c {m}^{2} }{2} = 24c {m}^{2} [/tex]
[tex]24c {m}^{2} = 24c {m}^{2} [/tex]
Pozdrawiam,
Michał
