Odpowiedź:
[tex]y=-9x^2-6x+2\\\\a=-9\ \ ,\ \ b=-6\ \ ,\ \ c=2\\\\\Delta=b^2-4ac\\\\\Delta=(-6)^2-4\cdot(-9)\cdot2=36+72=108\\\\\\p=-\frac{b}{2a}=-\frac{-6}{2\cdot(-9)}=-\frac{-6}{-18}=-\frac{1}{3}\\\\q=\frac{-\Delta}{4a}=\frac{-108}{4\cdot(-9)}=\frac{-108}{-36}=3\\\\W(-\frac{1}{3},3)[/tex]
[tex]f(x)=a(x-p)^2+q\\\\f(x)=-9(x-(-\frac{1}{3}))^2+3\\\\f(x)=-9(x+\frac{1}{3})^2+3[/tex]
