Odpowiedź:
a) [tex]4(\sqrt{3} )^{2} = 4\sqrt{3} * (\sqrt{3}) = 4\sqrt{3*3} = 4\sqrt{9} = 4*3 = 12[/tex]
b) [tex](2\sqrt{2} )^{2} = 2\sqrt{2} *2 \sqrt{2} = 4\sqrt{2*2} = 4\sqrt{4} = 4*2 = 8[/tex]
c)[tex]\sqrt{7} * 3\sqrt{7} = 3\sqrt{7*7} = 3\sqrt{49} = 3*7 = 21[/tex]
d) [tex]2\sqrt{3} * 5\sqrt{3} = 10\sqrt{3*3} = 10\sqrt{9} = 10*3 = 30[/tex]
e)[tex](\frac{2\sqrt{5} }{5}) ^{2} = \frac{(2\sqrt{5)^{2} } }{(5)^{2} } = \frac{(2\sqrt{5)*(2\sqrt{x5)} } }{(5)^{2} } = \frac{4\sqrt{5*5} }{(5^{2} )} = \frac{4\sqrt{25} }{(5)^{2} } = \frac{20}{(5)^{2} } = \frac{20}{25} = \frac{4}{5}[/tex]
f) [tex](\frac{2}{3} \sqrt{6} )^{2} = (\frac{2}{3} \sqrt{6} )* (\frac{2}{3} \sqrt{6} ) = \frac{4}{9}\sqrt{6*6} = \frac{4}{9} \sqrt{36} = \frac{4}{9}*6 = \frac{8}{3} = 2 \frac{2}{3}[/tex]
g) Niestety nie umiem tego przykładu zrobić :(
h) [tex]-3\sqrt{15} * 2\sqrt{15} = -6\sqrt{15*15} = -6\sqrt{225} = -6*15 = -90[/tex]
Szczegółowe wyjaśnienie:
Mam nadzieję że pomogłam :)
