[tex]Dane: \\Pc = 180cm^2\\a = 5cm\\\\Szukane: \\H = ?\\\\Wzory: \\Pp = a^2\\Pb = aH\\Pc = 2Pp+4Pb\\\\Rozwiazanie: \\Pp = (5cm)^2=25cm^2\\Pb = 5cm*H\\180cm^2=2*25cm^2+4*(5cm*H)\\180cm^2=50cm^2+4*(5cm*H) /-50cm^2\\130cm^2=4*(5cm*H) /:4\\32.5cm^2=5cm*H /:5cm\\6.5cm = H\\[/tex]
Odp. Wymiary prostopadloscianu to 5cm x 5cm x 6,5cm
