a)
[tex]x + \frac{1}{3} = 7\\\\x = 7-\frac{1}{3}\\\\x = 6\frac{2}{3}[/tex]
b)
[tex]3 - \frac{x}{2} = \frac{1}{3} \ \ /\cdot6\\\\18-3x=2\\\\-3x = 2 - 18\\\\-3x = -16 \ \ /:(-3)\\\\x = \frac{16}{3} = 5\frac{1}{3}[/tex]
c)
[tex]1 - 3x = \frac{1}{2}\\\\-3x = \frac{1}{2}-1\\\\-3x = -\frac{1}{2} \ \ /:(-3)\\\\x = \frac{1}{6}[/tex]
d)
[tex]\frac{1}{2}x + 1 = 4\\\\\frac{1}{2}x = 4-1\\\\\frac{1}{2}x = 3 \ \ /\cdot2\\\\x = 6[/tex]
