[tex]dane:\\I_{p} =2 \ A\\n_{p} = 100\\n_{p} = 1000\\szukane:\\I_{w} = ?\\\\\frac{I_{p}}{I_{w}} = \frac{n_{w}}{n_{p}}\\\\I_{w}\cdot n_{w} = I_{p}\cdot n_{p} \ \ /:n_{w}\\\\I_{w} = I_{p}\cdot\frac{n_{p}}{n_{w}}\\\\I_{w} = 2 \ A\cdot\frac{100}{1000}\\\\I_{w} = 0,2 \ A[/tex]
Odp. Natężenie uzyskane w obwodzie wtórnym wyniesie 0,2 A.
