[tex]dane:\\1 \ l \ wody = 1 \ kg\\a)\\m = 0,02 \ kg = 20 \ g\\d = 1\frac{g}{cm^{3}}\\b)\\m = 4 \ g\\d = 1\frac{g}{cm^{3}}\\szukane:\\V = ?\\\\Rozwiazanie\\\\a)\\d = \frac{m}{V} \ \ \rightarrow \ \ V = \frac{m}{d}\\\\V = \frac{20 \ g}{1\frac{g}{cm^{3}}} = 20 \ cm^{3}}\\\\b)\\V=\frac{m}{d}\\\\V = \frac{4 \ g}{1\frac{g}{cm^{3}}} = 4 \ cm^{3}}[/tex]
