Odpowiedź:
[tex]b)\\\\\frac{1}{4}-\frac{1}{2}=\frac{1}{4}-\frac{2}{4}=-\frac{1}{4}\\\\\\-\frac{7}{12}+\frac{3}{8}=-\frac{14}{24}+\frac{9}{24}=-\frac{5}{24}\\\\\\-3\frac{1}{5}-2\frac{1}{2}=-3\frac{2}{10}-2\frac{5}{10}=-5\frac{7}{10}\\\\\\1\frac{1}{6}-(-2\frac{1}{12})=1\frac{1}{6}+2\frac{1}{12}=1\frac{2}{12}+2\frac{1}{12}=3\frac{3}{12}=3\frac{1}{4}[/tex]
[tex]c)\\\\3,7-4\frac{2}{5}=3,7-4,4=-0,7\ \ \ \ \ \ lub\ \ \ \ 3,7-4\frac{2}{5}=\frac{37}{10}-\frac{22}{5}=\frac{37}{10}-\frac{44}{10}=-\frac{7}{10}\\\\\\-\frac{7}{8}+(-0,7)=-\frac{7}{8}-\frac{7}{10}=-\frac{35}{40}-\frac{28}{40}=-\frac{63}{40}=-1\frac{23}{40}\\\\\\1,4-(-1\frac{3}{4})=1,4+1\frac{3}{4}=1,4+1,75=3,15\\\\lub\\\\1,4+1\frac{3}{4}=1\frac{2}{5}+1\frac{3}{4}=1\frac{8}{20}+1\frac{15}{20}=2\frac{23}{20}=3\frac{3}{20}[/tex]
[tex]-2\frac{1}{6}-(-1,6)=-2\frac{1}{6}+1,6=-\frac{13}{6}+\frac{16}{10}=-\frac{65}{30}+\frac{48}{30}=-\frac{17}{30}[/tex]
