Odpowiedź:
[tex]a)\ \ 3(2\sqrt[3]{7}+3)=3\cdot2\sqrt[3]{7}+3\cdot3=6\sqrt[3]{7}+9\\\\\\b)\ \ 4(\frac{1}{2}\sqrt{5}+1)=\not4^2\cdot\frac{1}{\not2_{1}}\sqrt{5}+4\cdot1=2\sqrt{5}+4\\\\\\c)\ \ 2(2+4\sqrt{3})+2(\sqrt{3}-5)=2\cdot2+2\cdot4\sqrt{3}+2\cdot\sqrt{3}+2\cdot(-5)=\\\\=4+8\sqrt{3}+2\sqrt{3}-10=-6+10\sqrt{3}\\\\\\d)\ \ 2\sqrt{5}+3\sqrt{3}-4\sqrt{3}+5\sqrt{5}=7\sqrt{5}-\sqrt{3}\\\\\\e)\ \ 8(5\sqrt{2}-3)=8\cdot5\sqrt{2}-8\cdot3=40\sqrt{2}-24[/tex]
