Zapisz w postaci sumy.a)√11(4 −√11)b)(3 −√6)(5 + 2√6)

Odpowiedź :

Odpowiedź:

a)

√11(4 - √11) = 4√11 - √11 * √11 = 4√11 - 11

b)

(3 - √6)(5 + 2√6) = 15 - 5√6 + 6√6 - 2√6 * √6 = 15 + √6 - 2 * 6 =

= 15 + √6 - 12 = 3 + √6

[tex]Zadanie\\\\a)\\\\\sqrt{11}(4-\sqrt{11})=4\sqrt{11}-11\\\\b)\\\\(3-\sqrt{6})(5+2\sqrt{6})=15+ 6\sqrt{6}-5\sqrt{6}-12=3+\sqrt{6}[/tex]