[tex](-\frac{3}{4} )^{2} = (-\frac{3}{4} ) * (-\frac{3}{4}) = \frac{9}{16}[/tex]
[tex]\frac{9}{16} oraz \frac{3}{4} = \frac{9}{16} oraz \frac{12}{16}[/tex]
[tex]\frac{9}{16} < \frac{12}{16}[/tex]
Odp: Fałsz
