Równanie okręgu ma postać:
[tex](x-x_{s})^{2} + (y-y_{s})^{2} = r^{2}[/tex]
a)
[tex](x-3)^{2}+(y-7)^{2} = 64 \\\\S_{(x_{s},y_{s})}= (3; 7)\\\\r = \sqrt{64} = 8[/tex]
b)
[tex](x-\sqrt{2})^{2} + (y+\sqrt{3})^{2} = 8\\\\S(x_{s}, y_{s})} = (\sqrt{2}; -\sqrt{3})\\\\r = \sqrt{8} = \sqrt{4\cdot2} = 2\sqrt{2}[/tex]
