[tex]\frac{2^{7}\cdot5^{7}}{(10^{2})^{3}}\cdot\frac{1,3^{3}\cdot27}{3,9^{2}} = \frac{(2\cdot5)^{7}}{10^{6}}\cdot\frac{1,3^{3}\cdot3^{3}}{3,9^{2}} = \frac{10^{7}}{10^{6}} \cdot\frac{(1,3\cdot3)^{3}}{3,9^{3}} = 10\cdot\frac{3,9^{3}}{3,9^{2}}=10\cdot3,9 = 39[/tex]
Wyjaśnienie:
[tex]a^{m}\cdot a^{m} = a^{m+n}\\\\a^{m}:a^{n} = a^{m-n}\\\\a^{n}\cdot b^{n} =(a\cdot b)^{n}\\\\(a^{m})^{n} = a^{m\cdot n}[/tex]
