Twierdzenie Pitagorasa !!!
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Zad. 1
a = 6[tex]\sqrt{2}[/tex] [cm]
b[tex]\sqrt{2}[/tex] = 6
2b =6 [tex]\sqrt{2}[/tex]
b = 3[tex]\sqrt{2}[/tex] [cm]
c = [tex]\sqrt{(3\sqrt{5}) ^{2}+ (3\sqrt{9}) ^{2} }[/tex]
c = [tex]\sqrt{15 + 81}[/tex]
c = [tex]\sqrt{96}[/tex]
c = 4[tex]\sqrt{6}[/tex] [cm]
Zad. 2
P = [tex]\frac{(7\sqrt{2})^{2} }{2}[/tex]
P = 49 [cm²]
L = 4 · 7
L = 28
Zad. 3
P = 1/2 · 13 · 13
P = 84.5 [cm²]
L = 13 + 13 + 13[tex]\sqrt{2}[/tex]
L = 26 + 13[tex]\sqrt{2}[/tex]