Twierdzenie Pitagorasa !!!

Twierdzenie Pitagorasa class=

Odpowiedź :

Zad. 1

a = 6[tex]\sqrt{2}[/tex] [cm]

b[tex]\sqrt{2}[/tex] = 6

2b =6 [tex]\sqrt{2}[/tex]

b = 3[tex]\sqrt{2}[/tex] [cm]

c = [tex]\sqrt{(3\sqrt{5}) ^{2}+ (3\sqrt{9}) ^{2} }[/tex]

c = [tex]\sqrt{15 + 81}[/tex]

c = [tex]\sqrt{96}[/tex]

c = 4[tex]\sqrt{6}[/tex] [cm]

Zad. 2

P = [tex]\frac{(7\sqrt{2})^{2} }{2}[/tex]

P = 49 [cm²]

L = 4 · 7

L = 28

Zad. 3

P = 1/2 · 13 · 13

P = 84.5 [cm²]

L = 13 + 13 + 13[tex]\sqrt{2}[/tex]

L = 26 + 13[tex]\sqrt{2}[/tex]