Rozwiąże ktoś daje najj?

Rozwiąże Ktoś Daje Najj class=

Odpowiedź :

Odpowiedź:

1)

√243 = 3^5

3∛3 = 3^(1+1/3)

√√3 = 3^(1/4)

2)

0.2^(1/4)*√25 = 125^(1/4)

8√2*4∛2 = 128^(5/6)

1/36*(√6)²*36^(1/4) = 6^-(1/2)

3)

√27 = 3^(3/2)

5^(5/3) = (5^(1/3))^5

125^(1/4) = 5^(3/4)

√0.1 = 10^(-1/2)

√(11^5) = 11^(5/2)

(6^(1/3))^(1/4) = 6^(4/3)

11^(5/6) =  (11^(1/6))^5

5^-(2/3) = 0.4^(1/3)

(6^3)^(1/4) = 6^(3/4)

3^(4/5) = 81^(1/5)

11^(2/5) = 121^(1/5)

(6^(-4))^(1/3) = 6^(-4/3)