[tex]Zadanie\\\\2(tg\ 30^o-sin\ 45^o)\cdot(cos\ 45^o-ctg\ 60^o)=2(\frac{\sqrt{3} }{3}-\frac{\sqrt{2} }{2})\cdot(\frac{\sqrt{2} }{2}-\frac{\sqrt{3} }{3})=\\\\2(\frac{\sqrt{6} }{6}-\frac{3}{9}-\frac{2}{4}+\frac{\sqrt{6} }{6})=2(\frac{2\sqrt{6} }{6}-\frac{1}{3}-\frac{1}{2})= 2(\frac{\sqrt{6} }{3}-\frac{2}{6}-\frac{3}{6})=2(\frac{\sqrt{6} }{3}-\frac{5}{6})=\\\\ \frac{2\sqrt{6} }{3}-\frac{5}{3}=\frac{2\sqrt{6}-5 }{3}[/tex]
