Malqciaczekviz
Rozwiązane

DAJE NAJ I 20PKT
zapisz w najprostszej postaci i oblicz (⅗)⁴*5⁴
(⅗)⁴*(1 ⅔)⁵
Uprosc wyrażenia i oblicz
2⁸+2⁶/20​

Odpowiedź :

(3/5)4x (5/1)4= 81/625x625/1= 81/1x1/1=81

(3/5)4x (5/3)5= 81/625x3125/243= 27/125x625/81= 5/3= 1 2/3

2 8+2 6/2 4+4= 256+64/16+4= 320/20=16

Magdaviz

Odpowiedź:

[tex](\frac{3}{5})^4\cdot5^4=(\frac{3}{\not5_{1}}\cdot\not5^1)^4=3^4=81\\\\(\frac{3}{5})^4\cdot(1\frac{2}{3})^5=(\frac{3}{5})^4\cdot(\frac{5}{3})^5=(\frac{3}{5})^4\cdot(\frac{3}{5})^{-5}=(\frac{3}{5})^{4-5}=(\frac{3}{5})^{-1}=\frac{5}{3}=1\frac{2}{3}\\\\\\\\\dfrac{2^8+2^6}{20}=\dfrac{2^6\cdot(2^2+1)}{20}=\dfrac{2^6\cdot(4+1)}{20}=\dfrac{2^6\cdot\not5^1}{\not20_{4}}=\dfrac{2^6}{4}=\dfrac{2^6}{2^2}=2^{6-2}=2^4=16[/tex]

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