Witam.
[tex]a) \: 5 \sqrt{2} = \sqrt{ {5}^{2} } \times \sqrt{2} = \sqrt{25 \times 2} = \sqrt{50} [/tex]
[tex]b) \: 3 \sqrt{7} = \sqrt{ {3}^{2} } \times \sqrt{7} = \sqrt{9 \times 7 } = \sqrt{63} [/tex]
[tex]c) \: 2 \sqrt{5} = \sqrt{ {2}^{2} } \times \sqrt{5} = \sqrt{4 \times 5} = \sqrt{20} [/tex]
[tex]d) \: 3 \sqrt[3]{3} = \sqrt[3]{ {3}^{3} } \times \sqrt[3]{3} = \sqrt[3]{27 \times 3} = \sqrt[3]{81} [/tex]
[tex]e) \: 2 \sqrt[3]{5} = \sqrt[3]{ {2}^{3} } \times \sqrt[3]{5} = \sqrt[3]{8 \times 5} = \sqrt[3]{40} [/tex]
[tex]f) \: 4 \sqrt[3]{2} = \sqrt[3]{ {4}^{3} } \times \sqrt[3]{2} = \sqrt[3]{64 \times 2} = \sqrt[3]{128} [/tex]
Pozdrawiam,
Michał
