[tex]dane:\\v = 0,19\frac{m}{s}\\F = 40 \ N\\szukane:\\P = ?\\\\Rozwiazanie\\\\P = \frac{W}{t} = \frac{F\cdot s}{t} =F\cdot v\\\\P = 40 \ N\cdot0,19\frac{m}{s} = 40 \ kg\cdot\frac{m}{s^{2}}\cdot0,19\frac{m}{s} =40\cdot0,19 \ kg\cdot\frac{m^{2}}{s^{3}}}\\\\P = 7,6 \ W[/tex]
Odp. Szukana moc P = 7,6 W.
