42. Oblicz: daje NAJ
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[tex]a) \ (2\sqrt{7})^{2} = 2^{2}\cdot7 = 4\cdot7 = 28\\\\b) \ (\frac{3\sqrt{3}}{2})^{2} = \frac{9\cdot3}{4} = \frac{27}{4} = 6\frac{3}{4}=6,75\\\\c) \ 4\sqrt{5^{2}} = 4\cdot5 = 20\\\\d) \ \frac{1}{3}\sqrt{6}\cdot3\sqrt{6} = \sqrt{6^{2}} = 6\\\\e) \ 7\sqrt[3]{5^{3}} =7\cdot5 = 35\\\\f) \ (2\sqrt[3]{3})^{3} = 2^{3}\cdot3 = 8\cdot3 = 24[/tex]