[tex]\sqrt[3]{125}+\sqrt{81} =\sqrt[3]{6{3}}+\sqrt{9^{2}} = 5+9 = 14\\\\3\sqrt{6}^{2}+28 = 3\cdot6+28 = 18+28 = 46\\\\\sqrt[3]{9}^{3}+\sqrt{15}^{2} = 9+15 = 24[/tex]
[tex]\sqrt{12}\cdot\sqrt{3}-\sqrt[3]{2}\cdot\sqrt[3]{4} = \sqrt{12\cdot3} -\sqrt[3]{2\cdot4} = \sqrt{36}-\sqrt[3]{8} = 6-2 = 4\\\\\frac{\sqrt{72}+2\sqrt{2}}{\sqrt{2}} = \frac{\sqrt{36\cdot2}+\sqrt{2}}{\sqrt{2}} =\frac{6\sqrt{2}+2\sqrt{2}}{\sqrt{2}} = \frac{8\sqrt{2}}{\sqrt{2}} = 8[/tex]
