[tex]dane:\\m = 2 \ kg\\E_{p} = 40 \ J\\g = 10\frac{m}{s^{2}}\\szukane:\\h = ?\\\\E_{p} = mgh \ \ /:mg\\\\h = \frac{E_{p}}{mg}\\\\h = \frac{40 \ J}{2 \ kg\cdot10\frac{m}{s^{2}}} =\frac{40 \ kg\cdot\frac{m^{2}}{s^{2}}}{20 \ kg\cdot\frac{m}{s^{2}}} = 2 \ m[/tex]
