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Proszę o pomoc


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Odpowiedź :

Z.1.

a)[tex]\sqrt{99} =\sqrt{9*11} =3\sqrt{11}[/tex]

b) [tex]\sqrt{116} =\sqrt{16*11} =4\sqrt{11}[/tex]

c) [tex]\sqrt[3]{24} =\sqrt[3]{3*8} =2\sqrt[3]3}[/tex]

d) [tex]\sqrt[3]{-320} =\sqrt[3]{(-64)*5} = -4\sqrt[3]{5}[/tex]

Z.2.

a) [tex]5\sqrt{3}= \sqrt{25*3} =\sqrt{75}[/tex]

b) [tex]-3\sqrt[3]{2}=\sqrt[3]{(-27)*2}=\sqrt[3]{-54}[/tex]

c) [tex]5\sqrt[3]{-2} = \sqrt[3]{125*(-2)} =\sqrt[3]{-250}[/tex]

Z.3.

a) [tex]\frac{\sqrt[3]{9} *\sqrt[3]{2} }{\sqrt[3]{3}} =\sqrt[3]{\frac{18}{3}} =\sqrt[3]{6}[/tex]

b) [tex]\sqrt[3]{7}*\sqrt[3]{16}:\sqrt[3]{28}=\sqrt[3]{\frac{7*16}{28}} =\sqrt[3]{\frac{112}{28}} =\sqrt[3]{4}[/tex]

Z.4.

a) [tex]\frac{\sqrt[3]{40}}{\sqrt[3]{5} } =\sqrt[3]{\frac{40}{5} } =\sqrt[3]{8}=2[/tex]

b) [tex]\sqrt[3]{10} *\sqrt[3]25} :\sqrt[3]{2}=\sqrt[3]{\frac{10*25}{2} } =\sqrt[3]{125} =5[/tex]

c) [tex]\frac{\sqrt{32}+\sqrt{2} }{\sqrt{2} } =\frac{\sqrt{16*2}+\sqrt{2} }{\sqrt{2} } =\frac{4\sqrt{2}+\sqrt{2} }{\sqrt{2} } =\frac{5\sqrt{2} }{\sqrt{2} } =5[/tex]

d) [tex]-2(5-\sqrt[3]{7} ) -3(2\sqrt[3]{7}+3)=-10+2\sqrt[3]{7}-6\sqrt[3]{7} -9=-19-4\sqrt[3]{7}[/tex]