Rozwiązane

Oblicz granice:

a) [tex]\left \ {{lim} \atop {x\to1}} \right. \frac{x-7}{x+2}[/tex]

b) [tex]\left \ {{lim} \atop {x\to2}} \right. \frac{x^{2} -4}{x+1} =[/tex]

c) [tex]\left \ {{lim} \atop {x\to2}} \right. \frac{3x- 6}{x-2} =[/tex]

d) [tex]\left \ {{lim} \atop {x\to-3}} \right. \frac{9 + 3x}{2x + 6} =[/tex]


Dziękuje :)

Odpowiedź :

Walizaztransformersviz
a) 1-7/1+2 = -2
b) 2^2 - 4 / 2+1 = 0
c) lim ( 3x-6 )
x -> 2
lim ( x-2 )
x -> 2
0
0
lim (3x-6 / x-2)
x -> 2
lim (3(x-2) / x-2 )
x -> 2
lim (3)
x -> 2
3
d) (9+3*3/2*3+6) = 3/2 = 1 1/2

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