[tex]dane:\\m = 5 \ kg\\t = 4 \ s\\\Delta v = 3\frac{m}{s}\\szukane:\\F = ?\\\\Rozwiazanie\\\\Z \ II \ zasady \ dynamiki\\a = \frac{F}{m}\\oraz\\a = \frac{\Delta v}{t}\\\\\frac{F}{m} = \frac{\Delta v}{t}\\\\F\cdot t =m\cdot \Delta v \ \ /:t\\\\F = m\cdot\frac{\Delta v}{t}\\\\F = 5 \ kg\cdot\frac{3\frac{m}{s}}{4 \ s} = 5 \ kg\ \cdot0,75\frac{m}{s^{2}}\\\\F = 3,75 \ N[/tex]
Odp. Na ciało działa siła o wartości 3,75 N.
