[tex]c)\\\\\frac{2\frac{1}{8}-1\frac{2}{3}}{1\frac{3}{8}:1\frac{1}{3}}=\frac{\frac{17}{8}-\frac{5}{3}}{\frac{11}{8}:\frac{4}{3}} = \frac{\frac{51}{24}-\frac{40}{24}}{\frac{11}{8}\cdot\frac{3}{4}} =\frac{\frac{11}{24}}{\frac{33}{32}} =\frac{11}{24}\cdot\frac{32}{33} = \frac{11}{33}\cdot\frac{32}{24} = \frac{1}{3}\cdot\frac{4}{3} = \frac{4}{9}[/tex]
