Odpowiedź:
[tex] log_{3}(81) = log_{3}( {3}^{4} ) = 4 \\ log_{2}( \frac{1}{32} ) = log_{2}( {2}^{ - 5} ) = - 5 \\ log_{5}( \sqrt{125} ) = log_{5}( {5}^{ \frac{3}{2} } ) = \frac{3}{2} \\ log_{3}( 3 {}^{ - \frac{3}{2} } ) = - \frac{3}{2} \\ \\ log_{2}( {2}^{ \frac{5}{2} } ) = \frac{5}{2} \\ [/tex]
[tex] log_{2}( {2}^{ - 4} ) = - 4[/tex]
