Odpowiedź :
[tex]A) \ -3a + 4a - a = 0\\\\B) \ 3a+2b-4a+b = -a+3b\\\\C) \ 5(d+2)-3d+4 = 5d + 10 - 3d + 4 = 2d+14[/tex]
A. -3a + 4a - a = a - a = 0
B. 3a + 2b - 4a + b = -a + 3b
C. 5(d + 2) -3d + 4 = 5d + 10 - 3d + 4 = 2d + 14
[tex]A) \ -3a + 4a - a = 0\\\\B) \ 3a+2b-4a+b = -a+3b\\\\C) \ 5(d+2)-3d+4 = 5d + 10 - 3d + 4 = 2d+14[/tex]
A. -3a + 4a - a = a - a = 0
B. 3a + 2b - 4a + b = -a + 3b
C. 5(d + 2) -3d + 4 = 5d + 10 - 3d + 4 = 2d + 14