[tex]dane:\\m = 13 \ t = 13 \ 000 \ kg\\v = 60\frac{km}{h} = 60\cdot\frac{1000 \ m}{3600 \ s} = \frac{50}{3}\frac{m}{s}\\szukane:\\E_{k} = ?\\\\Rozwiazanie\\\\E_{k} = \frac{1}{2}mv^{2}\\\\E_{k} = \frac{1}{2}\cdot13000 \ kg\cdot(\frac{50}{3}\frac{m}{s})^{2}} = 6500 \ kg\cdot\frac{2500 \ m^{2}}{9 \ s^{2}}\approx1 \ 805 \ 556 \ J \approx1,806 \ MJ[/tex]
