Odpowiedź:
zad 2
a)
y = (2x - 4)(2x - 1)
2x - 4 = 0 ∨ 2x - 1 = 0
2x = 4 ∨ 2x = 1
x = 4/2 ∨ x = 1/2
x = 2 ∨ x = 1/2
x₀ = { 1/2 , 2 }
Postać ogólna
y = (2x - 4)(2x - 1) = 4x² - 8x - 2x + 4 = 4x² - 10x + 4
b)
y = (2 -3x)(x + 4)
(2 - 3x)(x + 4) = 0
2 - 3x = 0 ∨ x + 4 = 0
- 3x = - 2 ∨ x = - 4
3x = 2 ∨ x = - 4
x = 2/3 ∨ x = - 4
x₀ = { - 4 , 2/3 }
Postać ogólna
y = (2 - 3x)(x + 4) = 2x - 3x² + 8 - 12x = - 3x² - 10x + 8
c)
y = (2x + 1)(3x + 1)
(2x + 1)(3x + 1) = 0
2x + 1 = 0 ∨ 3x + 1 = 0
2x = - 1 ∨ 3x = - 1
x = - 1/2 ∨ x = - 1/3
x₀ = { - 1/3 , - 1/2 }
Postać ogólna
y = (2x + 1)(3x + 1) = 6x² + 3x + 2x + 1 = 6x² + 5x + 1
