Obliczenia :
[tex]\frac{16}{\sqrt{12}+\sqrt{75}}=\frac{16}{\sqrt{4\cdot3}+\sqrt{25\cdot3}}=\frac{16}{\sqrt{2^2\cdot3}+\sqrt{5^2\cdot3}}=\frac{16}{2\sqrt3+5\sqrt3}=\\\\=\frac{16}{7\sqrt3}=\frac{16}{7\sqrt3}\cdot\frac{\sqrt3}{\sqrt3}=\frac{16\sqrt3}{7\sqrt{3^2}}=\frac{16\sqrt3}{7\cdot3}=\frac{16\sqrt3}{21}[/tex]
