Odpowiedź:
a.
[tex] - 2 \frac{3}{4} \times 2 \frac{1}{2} = - \frac{11}{4} \times \frac{5}{2} = - \frac{55}{8} = 6 \frac{7}{8} [/tex]
b.
[tex] - 7 \frac{1}{5} \div ( - 4 \frac{1}{5} ) = - \frac{36}{5} \div - \frac{21}{5} = - \frac{36}{5} \times - \frac{5}{21} = \frac{36}{21} = 1 \frac{15}{21} [/tex]
c.
-2,5*(-4,08)=10,2
d. pozbądź się możliwych zer po przecinku
2,8:7=0,4
e.
[tex]3 \frac{2}{5} \div 1 \frac{1}{5} + 1 \frac{2}{3} \times 3 \frac{3}{5} = \frac{17}{5} \div \frac{6}{5} + \frac{5}{3} \times \frac{18}{5 } = \frac{17}{5} \times \frac{5}{6} + \frac{5}{3} \times \frac{18}{5} = \frac{17}{6} + 6 = 8 \frac{5}{6} [/tex]
f.
[tex]3 \frac{1}{6} + ( - 6 \frac{2}{5} ) - ( - 4 \frac{1}{3} ) = 3 \frac{5}{30} - 6 \frac{12}{30} + 4 \frac{10}{30} = - 3 \frac{7}{30} + 4 \frac{10}{30} = 1 \frac{3}{30} = 1 \frac{1}{10} [/tex]
