Odpowiedź:
Szczegółowe wyjaśnienie:
A)
[tex]\sqrt{50}= \sqrt{25*2}=5\sqrt{2} \\\sqrt{28} =\sqrt{4*7} =2\sqrt{7} \\\sqrt{72} = \sqrt{36*2} =6\sqrt{2} \\\sqrt{200} =\sqrt{100*2}=10\sqrt{2} \\\sqrt{1800} =\sqrt{900*2} = 30\sqrt{2} \\\\[/tex]
B)
[tex]\sqrt[3]{16} = \sqrt[3]{8*2} = 2\sqrt[3]{2} \\\sqrt[3]{24} = \sqrt[3]{8*3} = 2\sqrt[3]{2} \\\sqrt[3]{-128} = \sqrt[3]{64*(-3)} = 4\sqrt[3]{-3} \\\sqrt[3]{3000} = \sqrt[3]{1000*3} =10\sqrt[3]{3}[/tex]
