[tex]dane:\\v_{o} = 0\\t = 4 \ s\\g = 10\frac{m}{s^{2}}\\szukane:\\v = ?\\h = ?[/tex]
Rozwiązanie
Prędkość:
[tex]v = g\cdot t\\\\v = 10\frac{m}{s^{2}}\cdot4 \ s = 40\frac{m}{s}\\\\40\frac{m}{s} = 40\cdot\frac{\frac{1}{1000}km}{\frac{1}{3600}h} = 40\cdot3,6 \ \frac{km}{h}= 144\frac{km}{h}[/tex]
Wysokość:
[tex]h = \frac{1}{2}gt^{2}\\\\h = \frac{1}{2}\cdot10\frac{m}{s^{2}}\cdot(4 \ s)^{2}\\\\h = 80 \ m[/tex]