[tex]\sqrt{\frac{1}{4}}-\frac{1}{2}*(3-\sqrt{64})=\frac{1}{2}-\frac{1}{2}*(3-8)=\frac{1}{2}-\frac{1}{2}*(-5)=\frac{1}{2}+\frac{5}{2}=\frac{1}{2}+2\frac{1}{2}=3\\\\\\\frac{\sqrt{26^2}}{\sqrt{49}+\sqrt{36}}*0,0001=\frac{26}{7+6}*0,01=\frac{26}{13}*0,01=2*0,01=0,02\\\\\\\sqrt{8-\frac{8}{9}}-\sqrt{(\frac{8}{9})^2}=\sqrt{7\frac{1}{9}}-\frac{8}{9}=\sqrt{ \frac{64}{9}}-\frac{8}{9}=\frac{8}{3}-\frac{8}{9}=\frac{24}{9}-\frac{8}{9}=\frac{16}{9}=1\frac{7}{9}\\\\\\15+2*(\sqrt{5})^2+\sqrt{0}=15+2*5+0=15+10=25\\\\\\\sqrt{2\frac{1}{4}}-\sqrt{\frac{1}{4}}=\sqrt{ \frac{9}{4}}- \frac{1}{2}=\frac{3}{2}-\frac{1}{2}=\frac{2}{2}=1[/tex]
[tex]\frac{16+\sqrt{6}}{16}*\sqrt{16}=\frac{16+4}{16}*4= \frac{20}{\not{16}^4}*\not{4}^1=\frac{20}{4}=5[/tex]
