Zadanie z matematyki pls dam naj

(pierwiastek =V


ZADANIE

(V3)^2=


3V3^3=


V(-3)^2=


(3V3)^3=


(3V6)^2=


V5*3V5=


(3V2/5)^2=


Odpowiedź :

[tex](\sqrt{3})^{2} = 3\\\\3\sqrt{3}^{3} =3\cdot\sqrt{3}^{2}\cdot\sqrt{3}=3\cdot3\cdot\sqrt{3} = 9\sqrt{3}\\\\\sqrt{(-3)^{2}} = \sqrt{9} = 3\\\\(3\sqrt{3})^{3} = 3^{3}\cdot\sqrt{3}^{3} = 27\cdot3\cdot\sqrt{3} = 81\sqrt{3}\\\\(3\sqrt{6})^{2} = 3^{2}\cdot(\sqrt{6})^{2} = 9\cdot 6 = 54\\\\\sqrt{5}\cdot3\sqrt{5} = 3\sqrt{5\cdot5} = 3\cdot 5 = 15\\\\(3\sqrt{\frac{2}{5}})^{2} = 3^{2}\cdot(\sqrt\frac{2}{5})^{2}=9\cdot\frac{2}{5} = \frac{18}{5} = 3\frac{3}{5}[/tex]

Viz Inne Pytanie