Odpowiedź:
Szczegółowe wyjaśnienie:
a)
AC=12
BC=5
[tex]x^{2} = 12^{2} + 5^{2}\\x^{2} =144+25\\x^{2} =\sqrt{169} \\x = 13[/tex]
b)
AC=2
BC=6
[tex]x^{2} =2^{2} + 6^{2} \\x^{2} = 4 +36\\x^{2} = \sqrt{40} \\x =6[/tex]
c)
BC=4
[tex]x^{2} =2^{2} +4^{2} \\x^{2} = 4+16\\x^{2} =\sqrt{20}\\x =4[/tex]
