[tex]dane:\\F_1 = 200 \ N\\S_1 = 0,1 \ m^{2}\\S_2 = 4 \ m^{2}}\\szukane:\\F_2 = ?\\\\Rozwiazanie\\\\Z \ twierdzenia \ Pascala\\\\\frac{F_1}{S_1} = \frac{F_2}{S_2} = p = constans\\\\F_2\cdot S_1 = F_1\cdot S_2 \ \ /:S_1\\\\F_2 = F_1\cdot\frac{S_2}{S_1}\\\\F_2 = 200 \ N\cdot\frac{4 \ m^{2}}{0,1 \ m^{2}}\\\\F_2 = 200 \ N \cdot 40\\\\F_2 = 8 \ 000 \ N = 8 \ kN[/tex]
